4y^2-8=5/x

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Solution for 4y^2-8=5/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*y^2-8 = 5/x // - 5/x

4*y^2-(5/x)-8 = 0

4*y^2-5*x^-1-8 = 0

-5*x^-1 = -(4*y^2-8) // : -5

x^-1 = (8-(4*y^2))/(-5)

-1 < 0

1/(x^1) = (8-(4*y^2))/(-5) // * x^1

1 = x^1*((8-(4*y^2))/(-5)) // : (8-(4*y^2))/(-5)

-5*(8-4*y^2)^-1 = x^1

x = -5*(8-4*y^2)^-1

x = -5*(8-4*y^2)^-1

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